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Cannot Register Duplicate Name In This Scope

Insults are not welcome. This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL) Top Experts Last 24hrsThis month ppolymorphe 171 John Simmons / outlaw Join them; it only takes a minute: Sign up xml Parse Exception error when deserializing WPF up vote 0 down vote favorite I am having problems deserializing a xaml file and If you tried with my sample code and it works fine for you, Please let me know and attach the same code. this contact form

If you choose to participate, the online survey will be presented to you when you leave the Msdn Web site.Would you like to participate? You can find the TextBox in UserControl based the control type as below: http://stackoverflow.com/questions/974598/find-all-controls-in-wpf-window-by-type Then register the name to the TextBox. Why are LEDs in my home unaffected by voltage drop? And sorry for that I misunderstanding your mean.

Your Email This email is in use. Source=PresentationFramework StackTrace: at System.Windows.ResourceDictionary.RegisterName(String name, Object scopedElement) at System.Xaml.NameScopeDictionary.RegisterName(String name, Object scopedElement) at System.Xaml.XamlObjectWriter.RegisterName(ObjectWriterContext ctx, String name, Object inst, XamlType xamlType, INameScope nameScope, INameScope parentNameScope, Boolean isRoot) YaBB Forum Software © 2000-2010. Treat my content as plain text, not as HTML Preview 0 … Existing Members Sign in to your account ...or Join us Download, Vote, Comment, Publish.

HomeHelpSearchLoginRegister The MindFusion Forums › Flow Diagramming Components › WPF › Problem with custom component (Moderator: Forum Admin) ‹ Previous Topic Book your seat now >> TreeView.zip Back to Top Close .NET TOOLBOX DevCraft MOBILE APP DEVELOPMENT Telerik Platform DIGITAL CONTENT & EXPERIENCE Progress Sitefinity SOFTWARE QUALITY Test Studio Get Products Free Re: Problem with custom component Reply #6 - Dec 18th, 2010 at 1:46am Stoyo me again, this time no is directly related with mindfusion component but im loosed with c# Optional Password I have read and agree to the Terms of Service and Privacy Policy Please subscribe me to the CodeProject newsletters Submit your solution!

Reply Radek says: April 22, 2011 at 1:21 pm To define Resource, use x:Key, not x:Name x:Key="TestDC" Reply Max says: June 18, 2012 at 4:14 am Thanks!!! General FAQ Ask a Question Bugs and Suggestions Article Help Forum Site Map Advertise with us About our Advertising Employment Opportunities About Us Ask a Question All Questions All Unanswered FAQ If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Wrong way on a bike path?

in fact I too not a professional developer. WebDéveloppement Web et Webmarketing Développement Web AJAX Apache ASP CSS Dart Flash / Flex JavaScript PHP Ruby & Rails TypeScript Web sémantique Webmarketing (X)HTML EDIEnvironnements de Développement Intégré EDI 4D Delphi Understand that English isn't everyone's first language so be lenient of bad spelling and grammar. You would need to point out the lines which seem to contain the error as indicated by the exception.

I am only an enthusiast who learn himself, I too not paid for my questions.) if I give less details people will blame that my questions are less informative. http://jklogic.blogspot.com/2012/03/cannot-register-duplicate-name-error.html I found one page where the Xaml designer wouldn't handle the page properly - it was throwing exceptions, and the editor was showing an error in the Xaml. Where do I sent the check? It is possible to define metric spaces from pure topological concepts without the need to define a distance function?

add this to Mybutton.xaml.cs: Code:static public DependencyProperty StrokeProperty = DependencyProperty.Register( "Stroke", typeof(Brush), typeof(Mybutton), new PropertyMetadata(Brushes.Black)); public Brush Stroke { get { return (Brush)GetValue(StrokeProperty); } set { SetValue(StrokeProperty, value); } } and http://sauvblog.com/cannot-register/cannot-register.html Terms of Service Layout: fixed | fluid CodeProject, 503-250 Ferrand Drive Toronto Ontario, M3C 3G8 Canada +1 416-849-8900 x 100 Forums Tutoriels Magazine FAQs Blogs Chat Newsletter Études Emploi Club Contacts These are below links says that it is not possible in usercontrol. MohammadIqbal 23-Feb-12 13:45pm I observed one fact . (I no longer want to ask question in this forum.

How to decline a postdoc interview if there is some possible future collaboration? foreach (UIElement child in grd.Children) { // do some more testing to make sure have got For example, load your XAML for the slideListView and then add new event handlers to this ListView object at this point. –Sheridan Jul 29 '13 at 12:21 Hi Sheridan, http://sauvblog.com/cannot-register/cannot-register-pdf-ocx.html I'm not sure what my options are here, but Can I create a new namescope for each TabItem?

Any help is appreciated wpf share|improve this question asked Jan 14 '11 at 7:33 Aks 2,08263273 add a comment| 1 Answer 1 active oldest votes up vote 2 down vote accepted Grid grd = (Grid) this.Content; // do simple testing to find out what the type is. You could also try simply removing the names from the controls and binding to them to replicate whatever functionality you named them for.

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Archives October 2014 September 2014 December 2013 July 2010 June 2010 May 2010 April 2010 March 2010 February 2010 January 2010 November 2009 September 2009 August 2009 July 2009 May 2009 this is really complex way to do this.I already have developed complex components.This way of avoid name of components is a big problem.This limitatin probably make to me desist buy this But I want to use the named parameter. Could you please check out my test solution and let me know if I am missing something.

Reply Dom says: May 25, 2011 at 11:27 am Keep this coming to the top of Google, saved me some head scratching, thanks for the post Reply Daniel Ionescu says: July Let's work to help developers, not make them feel stupid. please see the attached screen shot. http://sauvblog.com/cannot-register/cannot-register-with-dns-xp.html Creating controls then cloning them sounds a bit nasty!

Rangaswamy Tuesday, January 03, 2012 8:58 AM Reply | Quote 0 Sign in to vote Hi Rangaswamy, Thank you for your reply. Is that advisable? Does anyone know what I need to do here? I don't know what code you have in your code behind, but if it is simple, you can remove it and re-add it after loading the XAML.

How do I handle this? Can you please tell me, how it isthe controlalready registerd with name? Answer Petar Mladenov Admin 2885 posts Posted 12 Mar 2012 Link to this post Hi Ivan, I am not able to reproduce such issue neither in SL 4, nor in SL5 Répondre avec citation 0 0 28/07/2011,03h24 #3 Skyounet Expert éminent sénior Expert Silverlight et Windows PhoneInscrit enmars 2005Messages6380Détails du profilInformations personnelles :Sexe : Âge : 29Localisation : CanadaInformations professionnelles :Activité

Why is looping over find's output bad practice? What is my solution here? Treat my content as plain text, not as HTML Preview 0 … Existing Members Sign in to your account ...or Join us Download, Vote, Comment, Publish. Menu About Search for: ‘Cannot register duplicate name ‘XXX' in this scope' in VS2010 Here's a gotcha that was puzzling me yesterday.

How to install Mediawiki in Ubuntu I just started my first real job, and have been asked to organize the office party. The OK or FAIL column Compare elements iteratively How to delete the lines from a file that do not contain dot? As per the link, this.Content is the Mainpage.xaml. If you have any additional questions, please feel free to let me know.

Insults are not welcome. WPF0XamlParse Exception in wpf1XAML Parse Exception on project deploy error0How to solve Xaml Parse Exception? DeviceToolBoxItem dtb = new DeviceToolBoxItem(); string xamlString = XamlWriter.Save(dtb); Object content = XamlReader.Load(XmlReader.Create(new StringReader(xamlString))); //[Getting error here] So, the sample codedoes't suit for my scenario. Make user control which inherits from your control 2.