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Cannot Read Output Vhdl

So someone help me get through this simple and gate please. When I simulate this, C won't go highwhen A and B are high.Here is the codelibrary IEEE;use IEEE.STD_LOGIC_1164.ALL;use IEEE.STD_LOGIC_ARITH.ALL;use IEEE.STD_LOGIC_UNSIGNED.ALL;---- Uncomment the following library declaration if instantiating---- any Xilinx primitives in evan Tue, 06 Mar 2001 03:00:00 GMT me..#4 / 6 What do I do? I learn something every day.. this contact form

This is how we reduce the buffer usage in vhdl. Reply With Quote Quick Navigation Quartus II and EDA Tools Discussion Top Site Areas Settings Private Messages Subscriptions Who's Online Search Forums Forums Home Forums General General Altera Discussion Altera Forum WARNING:Xst:2170 - Unit andGate_VHDL : the following signal(s) form a combinatorial loop: C. If an image is rotated losslessly, why does the file size change? http://www.edaboard.com/thread255356.html

I was just trying to send the output to multiple locations, one of which was to the final output of the circuit and the other which would reset a counter. WR_ACK : OUT std_logic ); end fifo; This interface is given and I can't change is. Instead use a local signal that can be read both by the debug and regular port. –trondd Mar 11 '11 at 9:32 add a comment| up vote 2 down vote You

Privacy Policy Terms and Rules Help Connect With Us Log-in Register Contact Us Forum software by XenForo™ ©2010-2015 XenForo Ltd. Many thanks for helpful comments! This is really basic VHDL 101. Compare elements iteratively Why is looping over find's output bad practice?

Ignore it. 'status' is driven (by the output of the procedure), so there is no 'read' done on it. So someone help me get through this simple and gate please. Toggle navigation My Account Sign Out Sign In Language Toggle English Japanese Chinese Shopping Cart All Silicon Devices Boards and Kits Intellectual Property Support Documentation Knowledge Base Community Forums Partners Videos http://stackoverflow.com/questions/4106908/reading-out-ports-for-debugging VHDL coding tips and tricks Get interesting tips and tricks in VHDL programming Pages Home VHDL FAQs Example Codes Testimonials About me Homework or Project Support Us Disclaimer Contact me for

View solution in original post Message 2 of 4 (7,800 Views) Reply 0 Kudos All Replies bassman59 Teacher Posts: 6,500 Registered: ‎02-25-2008 Re: simple and gate can't be output in vhdl How can I fix this? In my code > the recod is more complex. UPGRADE YOUR BROWSER We have detected your current browser version is not the latest one.

You can, however read from an inout port, or a buffer (though support for a buffer signal is a little sketchy). https://forums.xilinx.com/t5/Synthesis/simple-and-gate-can-t-be-output-in-vhdl/td-p/50330 One way to see which features are supported is to browse the templates available for VHDL full designs, and you will see the various features in VHDL 2008 that are supported more stack exchange communities company blog Stack Exchange Inbox Reputation and Badges sign up log in tour help Tour Start here for a quick overview of the site Help Center Detailed Well, not in my contributions to the thread.... (;-) P -- Menchini & Associates | www.mench.com | tu sarai tutto tuo." P.O.

Thanks Olaf Olaf Petzold, Dec 19, 2005 #9 Mike Treseler Guest Olaf Petzold wrote: > Well, I have to ignore the warning or replace the procedure with > procedure body's http://sauvblog.com/cannot-read/cannot-read-usr.html entry_car_entered : out std_logic_vector(0 to entryCount-1) ); end entity controller_entity; architecture controller_v1 of controller_entity is signal cars_entered : std_logic_vector(0 to entryCount-1); component entry is port( clk : in std_logic; -- .... Message 3 of 4 (7,000 Views) Reply 0 Kudos gszakacs Teacher Posts: 8,784 Registered: ‎08-14-2007 Re: simple and gate can't be output in vhdl Options Mark as New Bookmark Subscribe Subscribe library IEEE; use IEEE.STD_LOGIC_1164.ALL; use IEEE.NUMERIC_STD.ALL; entity with_buffer is port( A : in unsigned(3 downto 0); B : in unsigned(3 downto 0);

According to Xilinx, buffers may give some problems during synthesis. You could do that element by element of entry_car_entered in the generate statement more than likely. How to minimize damage done by Java 7. navigate here It is a bogus warning.

Home Forum New Posts FAQ Calendar Community Groups Forum Actions Mark Forums Read Quick Links Today's Posts View Site Leaders Forum Rules Marketplace Shared Material FAQ About Us Register Chinese Forum Quote: > > Hi, > > I have a schematic where an inverter is connected to an output > > port. If your tools don't support it, whinge at the supplier until they do!

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If an image is rotated losslessly, why does the file size change? Mi cuentaBúsquedaMapsYouTubePlayNoticiasGmailDriveCalendarGoogle+TraductorFotosMásShoppingDocumentosLibrosBloggerContactosHangoutsAún más de GoogleIniciar sesiónCampos ocultosBuscar grupos o mensajes Connect with us All About Circuits Home Forums > Software & Microcomputing > Programmer's Corner > VHDL Component Mapping Reply to Does the same apply to > > VHDL? I know some compilers will default to the '93 version, meaning you'd need to change the version the compiler is compiling against. #5 Like Reply Show Ignored Content 1Next >

car_passed: out std_logic --Output to higher level ); end entity; architecture foo of entry is begin car_passed <= clk; end architecture; library ieee; use ieee.std_logic_1164.all; entity controller_entity is generic( entryCount : WHAT ARE EMPLOYEES REALLY DOING ONLINE^^^ 11. The source of buffer port can only be internal. his comment is here Join them; it only takes a minute: Sign up Reading OUT ports for debugging up vote 2 down vote favorite I have a FIFO which has an interface that looks something

Can clients learn their time zone on a network configured using RA? For the record, I was not trying to tie multiple outputs together, as that would violate all that I know about digital design (save for with the help of a tristate The VHDL code that was generated defined my output port as type OUT. The use of an internal signal I will try.

Because you have a procedure with status as a parameter, the synthesis tool thinks this is a source signal, and that it should therefore be in the sensitivity list. The previous value of C_dummy is added with the current value of A and B to form the current value of C_dummy. Simulation will have an additional delta delay when the intermediate signal is used, but this will not have any effect if test benches and written in a robust way. –Morten Zilmer EDIT: So my workaround works, which was to just create a bunch more intermediate signal lines which I used in my combinational logic.

Your purported error statement is associated with trying to read a port signal or interface list signal of mode out from googling. Chao, Jun 10, 2004, in forum: VHDL Replies: 4 Views: 2,211 Mike Treseler Jun 14, 2004 is there any way to convert modelsim wave output to text file? In Verilog, it is legal to define a > > signal as an output as well as a wire or reg. All simulation/synthesis tools will do the same.

Jennifer A. share|improve this answer answered Nov 5 '10 at 22:20 Brian Carlton 3,87842344 I would not recommend that. Related Forum Posts: VHDL Posted by layikun in forum: Homework Help Replies: 0 Views: 1,207 VHDL Posted by chintannayak2005 in forum: Programmer's Corner Replies: 1 Views: 919 Vhdl Posted by MilK Modelsim should have told you this also together with the 1st warning. -> Make a copy from the output signal, read the copy.

Duane Clark, Dec 18, 2005 #8 Olaf Petzold Guest > architecture behaviorial of foo is > signal status_i : status_t; > begin > status <= status_i; got the same Problem here: